Diferencia entre revisiones de «Partido 2»

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  \left|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0  & \rho\cdot f(\rho ) & 0 \end{matrix}\right|  = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho}  \cdot  ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} )  \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>
 
  \left|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0  & \rho\cdot f(\rho ) & 0 \end{matrix}\right|  = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho}  \cdot  ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} )  \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>
  
<math>\  =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}){\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}
+
<math>\  =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}}{\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}

Revisión del 00:17 7 dic 2022

[math]\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot \left|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} [/math]

[math]\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}}{\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}[/math]