Partido 2 - Historial de revisiones

Estela Serrano Briz en 22:50 6 dic 2022

2022-12-06T22:50:30Z

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Estela Serrano Briz en 22:17 6 dic 2022

2022-12-06T22:17:33Z

Estela Serrano Briz en 22:16 6 dic 2022

2022-12-06T22:16:49Z

Estela Serrano Briz en 22:15 6 dic 2022

2022-12-06T22:15:50Z

Estela Serrano Briz en 22:09 6 dic 2022

2022-12-06T22:09:46Z

Estela Serrano Briz en 22:05 6 dic 2022

2022-12-06T22:05:26Z

Estela Serrano Briz en 22:02 6 dic 2022

2022-12-06T22:02:57Z

Estela Serrano Briz en 22:01 6 dic 2022

2022-12-06T22:01:03Z

Estela Serrano Briz en 22:00 6 dic 2022

2022-12-06T22:00:33Z

Estela Serrano Briz en 21:55 6 dic 2022

2022-12-06T21:55:23Z

← Revisión anterior		Revisión del 22:50 6 dic 2022
Línea 2:		Línea 2:
	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>		\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>

−	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}}{\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}	+	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z} = [\frac{4}{3} \cdot (1 - \frac{1}{\rho^2}) + \frac{4}{3} \cdot (1 + \frac{1}{\rho^2})] \vec {e_z} = [\frac{4}{3} - \frac{4}{3\rho^2} + \frac{4}{3} + \frac{4}{3\rho^2}] \vec {e_z} = \frac{8}{3} \vec {e_z}

← Revisión anterior		Revisión del 22:17 6 dic 2022
Línea 2:		Línea 2:
	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>		\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>

−	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}){\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}	+	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}}{\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}

← Revisión anterior		Revisión del 22:16 6 dic 2022
Línea 2:		Línea 2:
	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>		\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>

−	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}}{\rho)} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}	+	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}){\rho} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}

← Revisión anterior		Revisión del 22:15 6 dic 2022
Línea 2:		Línea 2:
	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>		\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>

−	<math>\ =[\frac{\frac{4}{3} ρ -\frac{4}{3ρ}}{ρ}+\frac{\partial(\frac{4}{3} ρ -\frac{4}{3ρ})}{\partial ρ}]\vec{e_z}	+	<math>\ =(\frac{\frac{4}{3} \cdot (\rho -\frac{1}{\rho}}{\rho)} + \frac{\partial(\frac{4}{3} \cdot (\rho -\frac{1}{\rho})}{\partial \rho})\vec{e_z}

← Revisión anterior		Revisión del 22:09 6 dic 2022
Línea 1:		Línea 1:
	<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot		<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot
	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>		\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>
		+
		+	<math>\ =[\frac{\frac{4}{3} ρ -\frac{4}{3ρ}}{ρ}+\frac{\partial(\frac{4}{3} ρ -\frac{4}{3ρ})}{\partial ρ}]\vec{e_z}

← Revisión anterior		Revisión del 22:05 6 dic 2022
Línea 1:		Línea 1:
	<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot		<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot
−	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z}	+	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z} = (\frac{f(\rho )}{\rho} + \frac{\partial f(\rho)}{\partial\rho})\vec {e_z} </math>

← Revisión anterior		Revisión del 22:02 6 dic 2022
Línea 1:		Línea 1:
	<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot		<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot
−	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ~~\left (\left~~ ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) ~~\right )~~ \vec {e_z} ~~\right )~~	+	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \vec {e_z}

← Revisión anterior		Revisión del 22:01 6 dic 2022
Línea 1:		Línea 1:
	<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot		<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot
−	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot \left (\left ( f(\rho) + \rho \cdot \frac{\~~partialf~~(\rho)}{\partial\rho} ) \right ) \vec {e_z} \right )	+	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot \left (\left ( f(\rho) + \rho \cdot \frac{\partial f(\rho)}{\partial\rho} ) \right ) \vec {e_z} \right )

← Revisión anterior		Revisión del 22:00 6 dic 2022
Línea 1:		Línea 1:
	<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot		<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot
−	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] =	+	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] = \frac{1}{\rho} \cdot \left (\left ( f(\rho) + \rho \cdot \frac{\partialf(\rho)}{\partial\rho} ) \right ) \vec {e_z} \right )

← Revisión anterior		Revisión del 21:55 6 dic 2022
Línea 1:		Línea 1:
	<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot		<math>\ \bigtriangledown \times \vec u = \frac{1}{\rho} \cdot
−	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot \f(\rho)))] =	+	\left\|\begin{matrix} \vec {e_\rho} & \rho\cdot \vec {e_\theta } & \vec {e_z} \\ \frac{\partial}{\partial \rho } & \frac{\partial}{\partial \theta} & \frac{\partial}{\partial z} \\ 0 & \rho\cdot f(\rho ) & 0 \end{matrix}\right\| = \frac{1}{\rho} \cdot [\vec {e_z} \cdot (\frac{\partial}{\partial \rho } \cdot (\rho \cdot f(\rho)))] =